Dear Yang,
if the sphere was a border surface between two regions, then yes.
On 28.03.2019 14:24, yangt_at_ihep.ac.cn wrote:
>
> Dear Mikhail,
>
> Thanks. Sphere indeed has only one surface, but its normal
> direction is not the same but along the radius. If a parallel beam
> penetrates a sphere sphere, does it select the whole sphere area as
> the usrbdx area?
>
> Best regards!
>
> Yang
>
> -----原始邮件-----
> *发件人:*"Mikhail Polkovnikov <Михаил Полковников>" <pmk_at_ihep.ru>
> *发送时间:*2019-03-27 20:36:48 (星期三)
> *收件人:* yangt_at_ihep.ac.cn, "fluka-discuss_at_fluka.org"
> <fluka-discuss_at_fluka.org>
> *抄送:*
> *主题:* Re: [fluka-discuss]: problem with usrbdx area
>
> Dear Yang,
>
> Sphere has only one surface with known area. You can split a
> cylinder body using planes and count current between regions
> separated by a plane.
>
> Best regards,
> Mikhail
>
>
> On 27.03.2019 03:48, yangt_at_ihep.ac.cn wrote:
>>
>> Dear Mikhail,
>>
>> Thanks for your reply. But how to deal with the curved surface,
>> i.e., borders as cylindrical, sphere or anyother irregular surface?
>>
>> Best regards!
>>
>> Yang
>>
>>
>>
>> -----原始邮件-----
>> *发件人:*"Mikhail Polkovnikov <Михаил Полковников>" <pmk_at_ihep.ru>
>> *发送时间:*2019-03-27 02:20:38 (星期三)
>> *收件人:* yangt_at_ihep.ac.cn, fluka-discuss_at_fluka.org
>> *抄送:*
>> *主题:* Re: [fluka-discuss]: problem with usrbdx area
>>
>> Dear Yang,
>>
>>
>> I suggest you to use a plane as a border between two regions,
>> so split void region on several regions which has only one
>> border surface, as it already have been suggested:
>> http://www.fluka.org/web_archive/earchive/new-fluka-discuss/13362.html
>>
>>
>> Your several Void->Box borders, have become Void1->Box,
>> Void2->Box, Void3->Box, ..., Void6->Box with only one
>> rectangular surface as a border.
>>
>>
>> Best regards,
>> Mikhail
>>
>>
>>
>> On 25.03.2019 18:40, yangt_at_ihep.ac.cn wrote:
>>>
>>> Dear experts and users,
>>>
>>> Recently, I encounter a small problem with usrbdx area.
>>>
>>>
>>>
>>> As shown in the figure, void is a sphere region, box is a
>>> cubic region, and material filled in them is both vacuum.
>>>
>>> I select one-way current scoring and want to get the current
>>> per unit area. Assuming we don’t know in advance what is the
>>> concrete direction of particles entering the box, and then
>>> select the area equal to the contact area of void-> box, eg,
>>> the cubic surface area,
>>>
>>> the value of particle current per unit area is J1; however,
>>> in actual the particles’ direction may be perpendicular to
>>> one surface as the shadow section shown in the figure, if we
>>> choose this area as the contact area in usrbdx card and
>>> obtain the particle current/area equal to J2, now J1=1/6 J2,
>>> if we select the total surface area of box, we may
>>> underestimate the quantity current/area, so how should we
>>> choose the area?
>>>
>>> Best regards!
>>>
>>> Yang
>>>
>>
>
__________________________________________________________________________
You can manage unsubscription from this mailing list at
https://www.fluka.org/fluka.php?id=acc_info
Received on Sat Mar 30 2019 - 13:42:29 CET