Date: Wed, 20 Apr 2016 07:56:39 +0000
Hi Khan,
yes you can calculate attenuation coefficients. There are several builtin scoring options in fluka
with that you can extract the flux and attenuation at every position, which you can convert it to
your attenuation coefficient. Please look the lectures on scoring on our basic course.
FLUKA runs on linux, however you can use fluka with Virtualbox on any machine windows, mac, etc.
Check the FLUPIX distribution in the download section of fluka.
Best
Vasilis
________________________________
From: owner-fluka-discuss_at_mi.infn.it [owner-fluka-discuss_at_mi.infn.it] on behalf of Drsalahuddin Khan [drskhan_at_ksu.edu.sa]
Sent: Tuesday, April 19, 2016 12:30
To: Roman Savinov; fluka-discuss_at_fluka.org
Subject: [fluka-discuss]: Attenuation coefficient measurement
Dear members,
I just join FLUKA but before getting ahead can anyone helpe me out with these questions, i highly appreciate that,
Whether FLuka code alone can calcualte attenuation coefficient of any material with gamma or neutorn soource as source?
is this code only work on LINUX system or if i do have Fortran language it may work?
thank you for your reply.
Regards,
Dr.Khan
________________________________
From: owner-fluka-discuss_at_mi.infn.it <owner-fluka-discuss_at_mi.infn.it> on behalf of Roman Savinov <rsavinov_at_calpoly.edu>
Sent: Tuesday, April 19, 2016 10:31 AM
To: fluka-discuss_at_fluka.org
Subject: [fluka-discuss]: Dose profile due to GCR
Dear FLUKA experts,
I have an emission sphere of GCR and a spherical water target. My expectation is that I should get a decreasing profile of dose distribution along the target radius (highest value on the surface, lowest toward the center). However, what I do get is a randomized dose distribution:
[cid:41dea6d6-3c88-4fcb-8e30-b5ff9e6dcda9]
[cid:c207fa74-bcca-42ad-813f-91510476a639]
Looks like 60 cm of water shows no attenuation whatsoever.
Can someone take a look at my input file and let me know what I do wrong?
I also include 6 GCR source files for the proton to carbon nuclei.
thank you,
Roman
________________________________
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