From: Konstantin Batkov (firstname.lastname@example.org)
Date: Wed Sep 12 2007 - 18:02:07 CEST
Thank you for this explanation. I would also like to make clear the case of
the KINETIC energy.
My question is: Is it correct to calculate the sum of the kinetic energy of
secondaries using this code in mgdraw.f?
ENTRY BXDRAW ( ICODE, MREG, NEWREG, XSCO, YSCO, ZSCO )
if (MREG.eq.3 .and .NEWREG.eq.2) then
sum = sum + ETRACK - AM(JTRACK)
My problem is that I am studying different functions of energy/polar angles
of different secondaries using many different cuts, so I just can't utilize
the built-in facilities of FLUKA.
2007/9/12, Paola Sala <email@example.com>:
> If you compare total energies, you have to take into account also
> the total energy of the target nucleus in the initial state, and the
> total energy of the nuclear fragments in the final state, including the
> residual nucleus that will NOT exit from the target. This is indeed
> what fluka checks internally at each interaction.
> for instance, if you take a reaction like
> n,A --> 2n,A'
> where A=(A,Z) is the target nucleus and A'==(A-1,Z) is the residual
> nucleus, if you count only the exiting particles the balance will be
> 1 GeV in input ( few MeV kinetic energy are enough)
> 2 GeV in output (twice the neutron mass)
> Of course this is balanced by the mass difference between the target
> and residual nuclei ( I leave out binding energies....)
> even more striking : in a neutrino quasielastic interaction
> a few MeV projectile will give you a 1 GeV nucleon in the final state.
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