MuchÃsimas Gracias Francesc!!!!! Sos un CAPO!!!!
Regards,
Jilberto
> On Nov 9, 2018, at 5:48 PM, Francesc Salvat-Pujol <francesc.salvat.pujol_at_cern.ch> wrote:
>
> Hola Jilberto,
>
> For inspiration you may first want to examine a slightly simpler 1D case
> (sampling from a tabulated energy spectrum), as shown e.g. in
>
> http://www.fluka.org/web_archive/earchive/new-fluka-discuss/6798.html
>
> which contains an example spectrum and a custom source.f routine that
> samples from it. Note also the modification of the input file mentioned
> in the link. If you make a diff (or e.g. vim -d) with the distributed
> source.f (under usermvax/ in your FLUKA directory) you will see the
> modifications. In a nutshell, there is:
>
> - a block that loads a source spectrum from the provided file at
> initialization and prepares a cumulative function for sampling
> later,
>
> - a block which samples the kinetic energy from the histogram and
>
> - a block which carefully sets the sampled kinetic energy and
> calculates the modulus of the linear momentum (of course with the
> relativistic expression).
>
> You then compile your custom source.f
>
> $FLUPRO/flutil/fff source.f
>
> If there are no errors, this produces an object file which you then
> bundle into your custom binary.
>
> $FLUPRO/flutil/lfluka -m fluka -o tuejecutable source.o
>
> Depending on what you do, link with ldpmqmd (see the manual). Run as
> usual, but passing "-e tuejecutable" additionally.
>
> If I follow you correctly, you need instead to sample from a tabulated
> 2D distribution h(E,theta), given in terms of the energy E and a
> (polar?) angle theta. So it's a slight generalization of the foregoing.
> Stay alert for the integrals and the sampling of the polar angle (see
> below).
>
> I assume that the theta dependency is not trivial, i.e., that you have
> sufficiently different behaviors in theta at different energies
> (otherwise the stuff below can be greatly simplified...).
>
> Presumably you have h(E,theta) tabulated on a reasonably dense grid of
> energies E_i and angles theta_j. On paper, at each tabular energy you
> would do an integration on the sphere (azimuthal angle aside), Ã la
>
> g(E_i) = \int_0^pi d theta sin(theta) h(E_i,theta) ,
>
> so that g(E) gives you an energy distribution regardless of angle
> (treated below). In practice you evaluate it numerically in as
> reasonable a way as you can, but in any event not forgetting about the
> solid-angle element. In the same spirit as in the 1D case above, you may
> now use the tabulated g(E_i) to generate a cumulative distribution for
> the sampling of the kinetic energy.
>
> Once you have a sampled kinetic energy Esampled, you look for the
> "active" tabular interval verifying E_i <= Esampled < E_{i+1}. Use a
> homogeneously distributed random number (search in the manual for
> FLRNDM) to take E_i with probability (E_{i+1}-Esampled)/(E_{i+1}-E_i),
> and E_{i+1} otherwise (I do not write down exactly how because every
> time I get it wrong, but the idea is along these lines...).
>
> At each tabular energy E_i, you can keep the cumulative angular
> distribution in memory (do not forget the solid-angle element when
> integrating...) and use it to sample the polar angle in exactly the same
> spirit as above. It then remains to sample the azimuthal angle. Unless
> you have something else in mind, you can sample e.g. homogeneously in
> [0,2pi). With this you have all you need to set the initial direction in
> your source.f in terms of the director cosines using the variables
> TXFLK, TYFLK, TZFLK.
>
> ===============================================
> *************** WARNING... ********************
> ===============================================
>
> Things can go wrong when setting up schemes like the above by hand...
> Debug and test intensively before running any simulation. Make e.g. a 2D
> histogram of the sampled energies and angles and convince yourself that
> you are indeed sampling what was intended.
>
> As a final note, I do not know what degrees of freedom you have in
> preparing the input 2D source histogram, but any time there's a polar
> angle theta involved, a way to sleep well is to tabulate, integrate, and
> sample in terms of mu=cos(theta). Doing the change of variables you
> immediately see e.g.
>
> g(E_i) = \int_{-1}^1 d mu h(E_i,mu) ,
>
> that is, the term "sin(theta) d theta" in the solid-angle element
> becomes trivially "d mu" and you can mostly forget about faux pas :)
>
> Hope this is reasonably helpful/accurate!
>
> Un saludo,
>
> Cesc
>
> PS: scoring-wise, there should be nothing special.
>
> On Fri, Nov 09 2018, at 12:17 -0300, jilberto Zamora Saa wrote:
>>
>> Dear FLUKA experts,
>>
>> How I should do in case I want to define my own beam of particles, let say, I would like to provide a spectrum of muons which depend on energy and Zenit angle and then use it to see the fluence in a detector.
>>
>> any help is welcome
>>
>> regards,
>> Jilberto
>
> --
> Francesc Salvat Pujol
> CERN-EN/STI
> CH-1211 Geneva 23
> Switzerland
> Tel: +41 22 76 64011
> Fax: +41 22 76 69474
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Received on Tue Nov 13 2018 - 02:13:08 CET