Low-mat option

From: <yyc2011_at_mail.ustc.edu.cn>
Date: Thu, 1 Aug 2013 22:06:59 +0800 (CST)

  Dear Alberto,
 
  Thanks for your patient reply.
 
  I read your last email carefully.I have three questions to ask you.

C Free gas natural Carbon 296K ENDF/B-VIIR0 Y CARBON 6 -2 296 Y
   C Free gas natural Carbon 87K ENDF/B-VIIR0 Y CARBON 6 -2 87 Y
   C Free gas natural Carbon 4K ENDF/B-VIIR0 Y CARBON 6 -2 4 Y
   C Free gas natural Carbon 430K ENDF/B-VIIR0 Y CARBON 6 -2 430 Y
   C Graphite bound nat. Carbon 296K ENDF/B-VIIR0 Y CARBON 6 -3 296 Y
................................................................................
27Al Aluminium 27 296K ENDF/B-VIIR0 Y ALUMINUM 13 27 296 Y
27Al Aluminium 27 87K ENDF/B-VIIR0 Y ALUMINUM 13 27 87 Y
27Al Aluminium 27 4K ENDF/B-VIIR0 Y ALUMINUM 13 27 4 Y
27Al Aluminium 27 430K ENDF/B-VIIR0 Y ALUMINUM 13 27 430 Y
27Al Aluminium 27 SelfShielded 296K ENDF/B-VIIR0 Y ALUMINUM 13 1027 296 Y
27Al Aluminium 27 SelfShielded 87K ENDF/B-VIIR0 Y ALUMINUM 13 1027 87 Y
27Al Aluminium 27 SelfShielded 4K ENDF/B-VIIR0 Y ALUMINUM 13 1027 4 Y
27Al Aluminium 27 SelfShielded 430K ENDF/B-VIIR0 Y ALUMINUM 13 1027 430 Y

The first material listed with the name CARBON is:
   C Free gas natural Carbon 296K ENDF/B-VIIR0 Y CARBON 6 -2 296 Y

and the first with the name ALUMINUM is:
27Al Aluminium 27 296K ENDF/B-VIIR0 Y ALUMINUM 13 27 296 Y

  The first question,In your view,If these are the materials I want, LOW-MAT is not needed.
  It is not an error to have a LOW-MAT.Am I right?

  The second question,"It is needed, instead, if I need one of those who are not first."What do you mean?
  If I need the first CARBON£®C Free gas natural Carbon 296K£©and the second ALUMINUM£®27Al Aluminium 27 87K£©,
  I think,according your view,for this time,low-mat is needed.Right?

  The third question," You put it there, however,and you made a mistake!
  LOW-MAT CARBON 13. 27. 296. ALUMINUM
  which would mean: "Use for Carbon the cross sections of Aluminum"!!!!!!!!!"which is obviously meaningless.
  I don't understand what you said "Use for Carbon the cross sections of Aluminum,which is obviously meaningless".
  Could you explain this in detail?

  Best wishes,
  Chenyuan
Received on Thu Aug 01 2013 - 17:06:18 CEST

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