Hello!Thank you for your previous help!!!!!!!
I think that I corrected all error. Yield of helium-6 = 1.2 x 10 7 and
yield of protons = 4.02 × 10 8 to 1 mA. Therefore, I have following
questions:
1) We expect that yield of helium-6 will be more, because we are now
experimentally obtain about 4.5 x 10 7 helium-6 for 1 mA. Also, I'm
interested in the fact that yield of protons and helium-6 so very
different. Why is this so? I really asking you to look again at the
code,please.
2) Can I use the following command for the calculation of the 7Li
(g,p)6He cross section ?:
USRBIN 12. PROTON -41. TARGET
protons
USRBIN TARGET
Thank you very much!!!!!!
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Received on Sun Jul 19 2015 - 22:24:14 CEST