Hi,
You can run separate simulation, with different beams and with differrent BINS (for example for x=0,y=o and z=-0.001 run the simulation with BIN 21 and for second with BIN 22), and after in FLAIR, in Run-Data menu add for first detector the files of second detector with Files-Add command (for something like xy_21.bnn add the files xy001_fort.22). Select all files of this detector and run the Process command. You obtained one, combined bnn file, which can process as usual. I hope this helps you!
Cheerio!
Roby
________________________________________
Feladó: owner-fluka-discuss_at_mi.infn.it [owner-fluka-discuss_at_mi.infn.it] ; meghatalmazó: Christian Buhl Sorensen [christian.buhl.soerensen_at_cern.ch]
Küldve: 2014. szeptember 19. 9:10
Címzett: Bruno Alves Brenga Vieira; fluka-discuss_at_fluka.org
Tárgy: RE: [fluka-discuss]: beam
Hi Bruno!
No, as far as I'm aware, it's not possible to define multiple beams. I'm not sure what happens when you do that - if it runs, I guess it only takes the last beam-card into account.
A nice way to check how your beam-setup is working, is to use a userdump scoring.
(
http://www.fluka.org/fluka.php?id=man_onl&sub=81 ). Using a formatted output allows you to plot the particle trajectory (make sure to only run 1 particle!!!), very easily with e.g. gnuplot.
This is also very useful, to check if a particle trajectory is out of alignment, and hits a beam pipe wall, or the like.
I hope that's of little help. I can't help but be curious about what 'something' you're sorry about, though.
Cheerio!
Christian Buhl
________________________________________
From: owner-fluka-discuss_at_mi.infn.it [owner-fluka-discuss_at_mi.infn.it] on behalf of Bruno Alves Brenga Vieira [bruno.brenga_at_aluno.ibb.unesp.br]
Sent: 19 September 2014 03:49
To: fluka-discuss_at_fluka.org
Subject: [fluka-discuss]: beam
Hi guys, I'm with a doubt .. If I have a proton beam of 120Mev and define it at x =0 y =0 z = -0.001 can define more times that same beam like x =1 y =5 z =-5 and this will give me two beams with 120Mev?
the first with x =y =0 z= -0.001 and second x = 5 y = 1 z = -5?
thanks guys, sorry for something.
bruno brenga
Received on Fri Sep 19 2014 - 12:03:49 CEST