From: Alfredo Ferrari (alfredo.ferrari@cern.ch)
Date: Mon Oct 30 2006 - 15:52:16 CET
Katherine
that can work for a point like source, not for an extended one.
Which source are you trying to model (ie that would not be suitable for
generating a isotropic flux at the top of the atmosphere, it would rather
generate an infinite fluence at 90 deg).
Ciao
Alfredo
On Wed, 25 Oct 2006, Katherine Harine wrote:
> In going over some runs I have done,
> I want to make sure I have done the inputs correctly.
> If I have an isotropic source incident down on a plate in
> the x-y plane and I have the source a very small
> distance above the plane, will the following statements in the source.f
> file give me the isotropic flux incident on one side of the plate:
>
>
> TZFLK (NPFLKA) = - FLRNDM(XXX)
> XKPHI = TWOTWO * PIPIPI * FLRNDM(XXX)
> TXFLK (NPFLKA) = SIN(ACOS(TZFLK(NPFLKA))) * COS(XKPHI)
> TYFLK (NPFLKA) = SIN(ACOS(TZFLK(NPFLKA))) * SIN(XKPHI)
>
>
> Next, since particles go only in the minus Z direction and since detectors will normalize results to one incident particle, will my flux
> be 1.0 particle/cm^2/s integrated over the 2 Pi hemisphere?
> That is, isn't my 4 Pi integrated flux equal to 2.0 particles/cm^2/s?
>
> I hope this makes sense. I read the recent discussion on
> fluence and current on fluka-discuss and I hope I understand it correctly.
>
> - Katherine
>
>
>
>
>
>
>
>
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