Re: [fluka-discuss]: Scoring beta dose rate from a source

From: Stefan Roesler <sroesler_at_mail.cern.ch>
Date: Wed, 21 Jun 2017 13:55:58 +0200

Dear Thomas

The beta energies are well below 1.5MeV where the conversion coefficient
for effective dose drops (in fact set to zero below 5MeV, the last
tabulated point). Thus, the scoring returns zero values. If you are
interested in extremity doses you'll have to compute it yourself.

Cheers
Stefan



On Mon, 19 Jun 2017, Thomas Frosio wrote:

>
> Dear Fluka experts,
>
>  
>
> I am trying to compute a beta-dose rate coming from a radioactive source of
> 61Cu which is placed in a box of 8 cubic meter of air.
>
> I succeeded in getting a score on beta particles but not beta dose.
>
> I used the HI-PROPE card and a SPHE-VOL type in BEAMPOS card for the source
> characteristics.
>
> I added a RADDECAY card and a USRBIN score on DOSE-EQ associated with
> AUXSCORE to filter E+&E- particles.
>
> These parts of my input are described below:
>
>  
>
> DEFAULTS                                                             
> PRECISIO
>
> * Define the beam characteristics
>
> BEAM             1.0                                                 
> ISOTOPE
>
> HI-PROPE         29.       61.
>
> * Define the beam position
>
> BEAMPOS          0.0        1.       0.0       0.0       0.0         
> SPHE-VOL
>
>  
>
> RADDECAY          2.        1.              0.0     99999
>
>  
>
> * BetaDose
>
> AUXSCORE      USRBIN     E+&E-            DosEqBet                    EWT74
>
> DCYSCORE         -1.                      DosEqBet                   
> USRBIN
>
> USRBIN           10.   DOSE-EQ      -64.      100.      100.     
> 100.DosEqBet
>
> USRBIN         -100.     -100.     -100.      200.      200.      200. &
>
>  
>
> Unfortunately, I do not succeed in getting a score on beta dose. There are
> no values in my score.
>
> But when I score gamma dose equivalent or beta particles, I have a result.
>
> Could you please help me to fix this problem?
>
> In another way, how should be done the normalization if I want a result in
> Sv/h for 1 Bq of my source? I do not know if the result is given in pSv/s
> or in pSv.
>
>  
>
> I thank you by advance for your answer.
>
> Thomas
>
>
>

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Received on Wed Jun 21 2017 - 14:51:54 CEST

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