[fluka-discuss]: the neutron yield of 65Cu(p,n)65Zn action

From: 张刚 <zhangg_at_ihep.ac.cn>
Date: Tue, 10 Jul 2018 15:50:36 +0800 (GMT+08:00)

Dear FLUKA authors and users,

    I calculated the neutron yield of 65Cu(p,n)65Zn action when proton energy are 3.6MeV and 4MeV.I found that difference between the result is 50 times.As far as I know, the cross sections of the 65Cu(p,n)65Zn action are about 60mb and 100mb at 3.6MeV and at 4MeV.

     Can't FLUKA calculate the 65Cu(p,n)65Zn action at 3.6MeV?

     The mail attachment is input file.


     Could anyone tell me what is wrong in this process?

Thank you,
best regards,

zhang



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Received on Tue Jul 10 2018 - 11:20:45 CEST