Re: [fluka-discuss]: the neutron yield of 65Cu(p,n)65Zn action

From: Paola Sala <paola.sala_at_mi.infn.it>
Date: Sat, 14 Jul 2018 18:20:13 +0200

Dera Zhang
for the moment, FLUKA cross sections do not include sub-barrier
penetration for protons. This means that it cannot calculate 65Cu(p,n)65Zn
action at 3.6MeV
Regards
Paola
> Dear FLUKA authors and users,
>
> I calculated the neutron yield of 65Cu(p,n)65Zn action when proton
> energy are 3.6MeV and 4MeV.I found that difference between the result
> is 50 times.As far as I know, the cross sections of the 65Cu(p,n)65Zn
> action are about 60mb and 100mb at 3.6MeV and at 4MeV.
>
> Can't FLUKA calculate the 65Cu(p,n)65Zn action at 3.6MeV?
>
> The mail attachment is input file.
>
>
> Could anyone tell me what is wrong in this process?
>
> Thank you,
> best regards,
>
> zhang


Paola Sala
INFN Milano
tel. Milano +39-0250317374
tel. CERN +41-227679148

__________________________________________________________________________
You can manage unsubscription from this mailing list at https://www.fluka.org/fluka.php?id=acc_info
Received on Sat Jul 14 2018 - 19:39:18 CEST

This archive was generated by hypermail 2.3.0 : Sat Jul 14 2018 - 19:39:21 CEST