Dear Zafar,
if you make a projection on a plane (let’s say XZ, as it looks like from your plot), Flair automatically uses a cut of the geometry that corresponds to the central bin
of the USRBIN along that projection.
And, as your USRBINs are not symmetric with respect to the plane where the dump lies, the cut of the geometry superimposed in the plot does not correspond to the plane Y = 0,
but to Y=150 cm.
A possibility would be to superimpose a geometry plot created previously. Another possibility is to selected the appropriated slice, on which the dump lies.
For sake of clarity, both options are highlighted in the attached snapshot.
N.B. Keep in mind that selecting a slice of the USRBIN bin or making a projection (i.e. an average) has a substantially different meaning.
In order to complement my answer to the definition of the RCC, I will assume that your geometry sketch shows a top view, that I define as XZ plane.
In that case Hy is equal to zero, while Hx and Hz are to be computed from your layout. But I do not understand what you mean by “at an equal angle”.
Cheers,
Luigi
[cid:4697F654-E57F-49DB-B37C-AE3F16053DC3_at_esss.lu.se]
On 26 May 2015, at 13:09, Zafar Yasin <Zafar.Yasin_at_cern.ch<mailto:Zafar.Yasin_at_cern.ch>> wrote:
Dear Luigi,
Thank you for your prompt reply. Please see attached my original input file and a rough changed at an angle. My beam dump
is in the plane I am plotting and it is visible when I plot it with limited dimensions, excluding room and walls.
My revised beam dump is in one corner at the bottom of a room and is inclined at an angle and beam is at the opposite corner at the top (
as shown in the attached diagram , blue portion is beam dump, sandwiched in the concrete in brown color).
I think I need to include Hx, Hy, Hz, at an equal angle, to describe exact position of dump?
Best regards,
Zafar
________________________________
From: Luigi Salvatore Esposito
Sent: 26 May 2015 10:41
To: Zafar Yasin
Cc: fluka-discuss_at_fluka.org<mailto:fluka-discuss_at_fluka.org>
Subject: Re: [fluka-discuss]:
Dear Zafar,
about your first point, for sure it is possible to draw the boundaries of the target in the plot, provided that the target lies in the plane you are plotting.
If you post you input file, we could make a check.
Concerning the second point, I can suggest you two possibilities:
1) you can define an RCC with any possible orientation (see manual section 8.2.4.4). As an example
RCC cyl 0.0 0.0 0.0 0.0 -70.71067811865 70.710678118655 50.
is a cylinder 100 cm long and of 50 cm radius, rotated by 45 degrees around the x-axis
2) use the directive “start_transform”, refer to the manual section 8.2.5.3
Best regards,
Luigi
On 26 May 2015, at 09:24, Zafar Yasin <Zafar.Yasin_at_cern.ch<mailto:Zafar.Yasin_at_cern.ch>> wrote:
Dear FLUKA experts and users,
I have two simple points to clarify which I am not tracing out.
Firstly, I have an electron beam dump in a room and I want to see dose rate around the beam dump and
around the walls. In the dose rate contour plots, one is attached with this email, I am seeing the boundaries'/dimensions
of the wall and not seeing the boundaries/dimensions of the beam dump, although the beam dump is not so small, about
50 cm radius and 100 cm long. I have seen a few presentations , like from Anna Ferrari, etc where they have same type of
plots and dimensions can be clearly seen. How can I improve my contour plots?
Secondly, I am using RCC to define cylinders along z-axis , etc. If cylinders are not along z-axis but making an angle say 45
degree with z-axis then can it is possible using RCC or any other option to rotate cylinders? Similar is the case for beam direction,
at 45 degree angle with z-axis.
If any body can comment on these, thank you in advance.
Best regards,
Zafar Yasin
ELI
<Ian11_plot06.jpg>
<Ian11.inp><Ianxy1.inp><(531222116) dump+room.pdf>
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Received on Wed May 27 2015 - 14:27:54 CEST