# [fluka-discuss]: Re: Beam energy spread

From: Ferreira De Almeida Lourenco, Ana <am.lourenco_at_ucl.ac.uk>
Date: Wed, 3 Jun 2015 14:36:07 +0000

Hello Vasilis,

Thank you very much for your reply. I didn't know about the function evaluation section and I'm sure it will be very useful in the future.

Best wishes,

Ana

________________________________
De: Vasilis Vlachoudis <Vasilis.Vlachoudis_at_cern.ch>
Enviado: 3 de junho de 2015 12:42
Para: Ferreira De Almeida Lourenco, Ana; fluka-discuss_at_fluka.org

Hi Ana,

you have to convert the kinetic energy spread dT=dE in momentum spread dp
E^2 = m^2 + p^2 => 2*E*dE = 2*p*dp where E=T+m
In flair you have a function for it, check the F3.6 section Function evaluation
dT2dp(T,dT,m)
you can use it as

=-dT2dp(60*MeV, 0.5*MeV, Mp)

Don't forget the - to be interpreted as Gaussian spread

Cheers
Vasilis

________________________________
From: owner-fluka-discuss_at_mi.infn.it [owner-fluka-discuss_at_mi.infn.it] on behalf of Ferreira De Almeida Lourenco, Ana [am.lourenco_at_ucl.ac.uk]
Sent: 02 June 2015 15:17
To: fluka-discuss_at_fluka.org

Hello Fluka experts,

I would like to simulate a 60 MeV proton beam with an energy spread of 0.5 MeV. Using a BEAM card, it is possible to define the beam momentum spread in GeV/c, but I'm not familiar with this definition. How can I define the energy spread of the beam? Should it be 0.0005 or 0.0005*c?

Many thanks,

Ana

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Received on Wed Jun 03 2015 - 17:50:05 CEST

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